by Kitty Pashuk
This lesson from Algebra 1 course is for 13-14-year-olds or 8th and 9th school grades. Here you will find information about quadratic equations and their basic definitions. We will consider the types of quadratic equations and step-by-step algorithms for their solutions using detailed examples. Having mastered this topic, you will be ready to explore cubic equations and equations of the fourth degree.
Solving equations is the central theme of algebra, so knowing how to work with this concept is a significant math skill for each student.
What is a quadratic equation? It is a type of problem that deals with a variable multiplied by itself. In other words, it is an equation of the second degree.
Quadratic equations surround us almost everywhere. For example, they are applied to design a playground or calculate the area of the land.
Sometimes finding the solution can be a struggle. The lesson goal is to describe effective methods that will help learners solve quadratic equations easily. Let’s have a look at some of these approaches!
Examples of using quadratic equations in real life
The length of the plot of land is 8 meters greater than the width. What is the size of this plot?
Solution:
Let the width of the plot be x, then the length is (x + 8), and the area is x * (x + 8). According to the problem condition, the area is 425 m². Let's make the equation for finding the area: x * (x + 8) = 425.
Let’s expand the brackets and we will get a quadratic equation x² + 8x = 425.
If the right part of the equation ≠ 0, it is necessary to exchange everything to the left side (we replace the right side digits to the left using the opposite signs). As a result, we get x² + 8x - 425 = 0. An equation of this type is called quadratic. Knowing how to solve such equations, we can find the x values, therefore, calculate the length and width of the plot of the land.
Having solved this equation, we get:
x = 17 (meters) - the width of the plot of the land, (x + 8) = 25 (meters) - its length.
Answer: 17m, 25m.
Definition:
If the equation fits the form ax² + bx + c = 0, where x is a variable, a, b, c are some numbers, and a ≠ 0, then it is a quadratic equation. Number a is the first coefficient, b is the second coefficient, and c is a free term.
Examples:
Let's consider examples of quadratic equations and define the constituent terms:
Solutions of quadratic equations
Before learning the many ways of solving quadratic equations, you need to explore such concepts:
a complete quadratic equation (all coefficients are not equal to zero) and an incomplete quadratic equation (some coefficients are equal to zero).
Answer if the equation is complete or incomplete?
Solving complete quadratic equations:
Here is the equation of the form ax² + bx + c = 0. Let’s make sure all the coefficients are not equal to zero: b ≠ 0 and c ≠ 0, a ≠ 0. Now we can start solving this complete quadratic equation. Firstly, we need to find the number of roots of the equation or their absence by calculating the discriminant (D). For an equation of the form ax² + bx + c = 0, where
a ≠ 0, b ≠ 0 or c ≠ 0, we can calculate the discriminant value by the formula: D = b² - 4ac (it is highly significant to remember!).
The algorithm of solving complete quadratic equations
Examples:
3x² + x + 2 = 0
Solution:
x² - 6x + 9 = 0
Solution:
Examples
-x² + x = 0
Solution:
We can solve this incomplete quadratic equation using the form ax² + bx = 0:
-x² + x = 0
x * (-x + 1) = 0 → x = 0 → x = 0
-x + 1 = 0 x = 1
Answer: 0, 1.
3x² - 27 = 0
Solution:
Let’s solve the incomplete quadratic equation choosing the method based on the form ax² + c = 0:
3x² - 27 = 0
3 * (x² - 9) = 0
x² - 3² = 0 → (x - 3) = 0 → x = 3
(x + 3) = 0 x = -3
Answer: -3, 3.
5x² = 0
Solution:
We can apply the form ax² + c = 0 to solve this incomplete quadratic equation:
5x² = 0
x² = 0
x = 0
Answer: 0.
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